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  1. nstorm

    По ОДЗ икс строго больше двух
    u = (x-2)^log(3,x+1)
    log(3,u) = log(3,x-2) log(3,x+1)
    log(3,x-2) = log(3,u)/log(3,x+1) = log(x+1,u)
    (x+1)^log(3,x-2)  = (x+1)^ log(x+1,u) = u
    u + 2u = 3(x+1)^2
    u = (x+1)^2
    (x+1)^log(3,x-2) = (x+1)^2
    log(3,x-2) = 2
    x — 2 = 9
    x = 11
    ————
    проверяем
    12^log(3,9) + 2 * 9^log(3,12) = 3 * 144

    9^log(3,12)  = (3^log(3,12) )^2

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